When Push Comes to Shove...
By: Shaila Murthy
For my blog post, I decided to have one of my friends (Matt) push another one of my friends (Abby) across the ice in ice skates, so I could measure the force with which he pushed her.
For my blog post, I decided to have one of my friends (Matt) push another one of my friends (Abby) across the ice in ice skates, so I could measure the force with which he pushed her.
In order to find Abby's acceleration, I plugged this video into Logger Pro and used the graphing software to create a velocity vs. time graph. Then, I created a linear fit line and used the slope of that line as my approximate average acceleration (it is measured in inches on the graph because we did not have a meter stick or a ruler available at this location so I had to use a piece of paper as the reference...).
Once I had her acceleration, I set up my free body diagram and my skeleton force equations:
From there, I set up the equations with the values I had, with the goal of solving for the force "F" (the force with which Matt pushed Abby). I did find, however, that I was unable to calculate this without the coefficient of kinetic friction on ice, so I did look up that value in order to solve for my desired value.
By using the force equations, I calculated that the force Matt imposed on Abby has an approximate value of 12.09 N. 👍
Sources:
1.) Koning, JJ, et al. “Ice Friction During Speed Skating.” Journal of Biomechanics, 25 June 1992,
www.ncbi.nlm.nih.gov/pubmed/1517252.
Awesome backyard rink!
ReplyDeleteDid you find the coefficient of friction in the article or in an online lookup table? Just curious.
I found it within the abstract of the article, since I did not have access to the whole article (also, I'm afraid that is actually Victoria's backyard rink).
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